I am doing a simple steel ball drop test on glass to see if the glass passes the standards. We are dropping 1.18 inches (0.535kg) steel ball at the height of 51inches (1.295m). Now, I can calculate final velocity at the impact, but cannot calculate the actual impact force. One of the method is using F=(mgh)/s where s is the distance travelled after the impact as described in http://www.engineeringtoolbox.com/impact-force-d_1780.html However since steel ball is non-elastic so the travelled distance after the impact on rigid glass will be nearly ZERO, then the impact force becomes infinite. There must have been a report or analysis on this simple ball drop test. Can anyone help me? And please don't tell me about you need to know the elastic properties of materials or how long the bodies are in contact and others craps. It is straght forward situation I think anyone can assume assumptions and conditions. A Steel ball droping onto glass!