Finding initial velocity given displacement, time, and final velocity

  • Thread starter dudelol
  • Start date
  • #1
dudelol
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Homework Statement


A woman running at constant velocity speeds up and accelerates uniformly to the west by running 253 m west in 6.12 s. ff she ends up getting up to a velocity of 5.05 m/s w, how fast was she going originally? If she had run the same disance in 5.50 s, what would her average velocity have been during her acceleration?
vf = final velocity = 5.5m/s
x = displacement = 253m
t = 6.12 s
find vi?

Homework Equations


vf=vi+at
v=(xf-xi)/t

The Attempt at a Solution


I honestly am stumped on this question.
average velocity during the acceleration 253/6.12 =41.34 m/s
 

Answers and Replies

  • #2
1MileCrash
1,339
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This woman would be running at like 100 miles per hour, and then the problem says she ends up "getting up to" a velocity of 5.05 m/s. Something's wrong here.
 

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