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Finding initial velocity given displacement, time, and final velocity

  1. Oct 3, 2011 #1
    1. The problem statement, all variables and given/known data
    A woman running at constant velocity speeds up and accelerates uniformly to the west by running 253 m west in 6.12 s. ff she ends up getting up to a velocity of 5.05 m/s w, how fast was she going originally? If she had run the same disance in 5.50 s, what would her average velocity have been during her acceleration?
    vf = final velocity = 5.5m/s
    x = displacement = 253m
    t = 6.12 s
    find vi?
    2. Relevant equations
    vf=vi+at
    v=(xf-xi)/t

    3. The attempt at a solution
    I honestly am stumped on this question.
    average velocity during the acceleration 253/6.12 =41.34 m/s
     
  2. jcsd
  3. Oct 3, 2011 #2
    This woman would be running at like 100 miles per hour, and then the problem says she ends up "getting up to" a velocity of 5.05 m/s. Something's wrong here.
     
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