A woman running at constant velocity speeds up and accelerates uniformly to the west by running 253 m west in 6.12 s. ff she ends up getting up to a velocity of 5.05 m/s w, how fast was she going originally? If she had run the same disance in 5.50 s, what would her average velocity have been during her acceleration?
vf = final velocity = 5.5m/s
x = displacement = 253m
t = 6.12 s
The Attempt at a Solution
I honestly am stumped on this question.
average velocity during the acceleration 253/6.12 =41.34 m/s