- #1
allegro1993
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Homework Statement
Someone throws a rubber ball vertically upward from the roof of a building 8.00 m in height. The ball rises, then falls. It misses the edge of the roof, and strikes the ground. If the ball is in the air for 3.00 s, what was its initial velocity? (Disregard air resistance. a = -g = -9.81m/s2)
Homework Equations
Mostly these:
[tex]\Delta[/tex]y = 1/2ay([tex]\Delta[/tex]t)2
vy, f = ay[tex]\Delta[/tex]t
vy, f2 = 2ay[tex]\Delta[/tex]y
idk if there are equations that could be used to solve this easier.
The Attempt at a Solution
I'm completely stumped. I figured in order to find the initial velocity, I'd need to find the height of the peak. To find the height, you would need the time interval for the second half, which is after the ball reaches the peak.
All that is given time-wise is the overall time (3 seconds), and I have no idea how to find out how long it takes to reach the top of its arc.
Any help would be appreciated, I'm at a dead end.