Finding Inner Solutions for Singular Perturbation Problems

  • Thread starter Thread starter sara_87
  • Start date Start date
  • Tags Tags
    Perturbation
Click For Summary
SUMMARY

The discussion focuses on solving the singular perturbation problem defined by the differential equation \(\epsilon\frac{d^{2}u}{dx^{2}} +\frac{du}{dx} + e^{-x} = 0\) with boundary conditions \(u(0)=0\) and \(u(1)=1\). The user attempts to find the inner solution using the substitution \(x=\epsilon^2 y\) and reformulates the equation accordingly. The main challenge presented is selecting an appropriate value for \(n\) in the transformed equation, which is critical for proceeding with the solution.

PREREQUISITES
  • Understanding of singular perturbation theory
  • Familiarity with boundary value problems
  • Knowledge of differential equations and their solutions
  • Experience with variable substitution techniques in calculus
NEXT STEPS
  • Research methods for selecting appropriate values in perturbation expansions
  • Study the application of boundary layer theory in singular perturbation problems
  • Learn about the method of matched asymptotic expansions
  • Explore numerical methods for solving boundary value problems
USEFUL FOR

Students and researchers in applied mathematics, particularly those dealing with differential equations and singular perturbation problems, as well as educators looking for examples of boundary value problem solutions.

sara_87
Messages
748
Reaction score
0

Homework Statement



[tex]\epsilon[/tex][tex]\frac{d^{2}u}{dx^{2}}[/tex] +[tex]\frac{du}{dx}[/tex] + e-x = 0

0<x<1
u(0)=0
u(1)=1

Homework Equations





The Attempt at a Solution



i want to find the inner solution first
i used the substitution x=[tex]\epsilon[/tex]2y

i put that in the equation:

[tex]\epsilon[/tex][tex]\frac{1}{\epsilon}^2n[/tex]u'' +[tex]\frac{1}{\epsilon}^n[/tex]u' +[tex]\epsilon[/tex]^n y = 0
now i have to pick a value for n... how do i do that?
 
Physics news on Phys.org
epsilon is not meant to be floating that... sorry just imagine it's in line, any help would be much appreciated thanks in advance!
 

Similar threads

Replies
6
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K