Finding Inverse of a Transformation

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SUMMARY

The discussion centers on finding the inverse of a linear transformation T applied to polynomials in P_2(R). The transformation is defined as T(a_0 + a_1 x + a_2 x^2) = (a_0, a_0 + a_1 + a_2, a_0 - a_1 + a_2). The matrix representation of T is constructed using the standard basis vectors of P_2(R), resulting in the matrix [1 0 0; 0 1/2 1/2; -1 1/2 -1/2] for its inverse S. Verification through the multiplication T*S = I confirms the correctness of the inverse.

PREREQUISITES
  • Understanding of polynomial spaces, specifically P_2(R).
  • Familiarity with linear transformations and their matrix representations.
  • Knowledge of matrix operations, including row reduction and multiplication.
  • Basic concepts of inverse matrices and identity matrices.
NEXT STEPS
  • Study the properties of linear transformations in vector spaces.
  • Learn about the process of finding inverses of matrices in linear algebra.
  • Explore the application of transformations on polynomial functions.
  • Investigate the implications of the Rank-Nullity Theorem in relation to linear transformations.
USEFUL FOR

Students and educators in mathematics, particularly those focusing on linear algebra and polynomial transformations, as well as anyone seeking to deepen their understanding of matrix operations and inverses.

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Homework Statement



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The Attempt at a Solution


Suppose we take an arbitrary polynomial in [itex]P_2 (R)[/itex], call this [itex]a_0 + a_1 x + a_2 x^2[/itex]

[itex]T(a_0 + a_1 x + a_2 x^2) = (a_0, a_0 + a_1 + a_2, a_0 - a_1 + a_2)[/itex]

Now, I was under the impression that I could construct a matrix for T by showing what T does to each of the standard basis vectors of [itex]P_2 (R)[/itex], these being the set [itex]1,x,x^2[/itex].

Doing some mapping: [itex]T(1 + 0x + 0x^2) = (1,1,1), T(0 + 1x + 0x^2) = (0,1,-1), T(0+0x+1x^2) = (0,1,1)[/itex].

Thus my matrix for T has these outputs as its columns. Via some elementary row reduction I concluded that the matrix (with semicolons indicating the end of a row) [1 0 0;0 1/2 1/2;-1 1/2 -1/2] is the inverse of T, call it S.

Moreover, it can be checked that T*S = I, which leads me to suspect that I have the write answer. Does this look about right?
 
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