Finding Joint PDF of Two Exponential Random Variables

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To find the joint PDF of two independent exponential random variables, the joint density function is the product of their individual PDFs. For the given variables, Y has a parameter λ=4 and X has λ=3, leading to their respective PDFs. The correct approach to find the PDF of W=X+Y involves using the convolution of the two PDFs, not the expected value formula. A referenced article clarifies the correct method for calculating the density of the sum of independent random variables. The discussion highlights the importance of understanding independence in probability density functions.
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Can anyone tell me how to find the joint PDF of two random variables? I can't seem to find an explanation anywhere. I'm trying to solve a problem but I'm not sure where to go with it:

Y is an exponential random variable with parameter \lambda=4. X is also an exponential random variable and independent of Y with \lambda=3.. Find the PDF f_W(w), where W=X+Y.

I know that I simply use:

f_W(w) = \int\int (x+y) f_{X,Y}(x,y)dydx

The problem is that I don't know how to find their joint PDF. I know their PDF's separately:


f_X(x)=\left\{\begin{array}{cc}3e^{-3x},&amp;<br /> x\geq 0\\0, &amp; otherwise\end{array}\right.

f_Y(y)=\left\{\begin{array}{cc}4e^{-4x},&amp;<br /> x\geq 0\\0, &amp; otherwise\end{array}\right.

Would this help me in anyway? Please help.
 
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the joint density function is simply the product of the individual density functions
see here under independence:
http://en.wikipedia.org/wiki/Probability_density_function
in that article you also find the correct formula for the density of X+Y, what you have there seems to be the formula for E[X+Y] imho
 
judoudo said:
the joint density function is simply the product of the individual density functions
see here under independence:
http://en.wikipedia.org/wiki/Probability_density_function
in that article you also find the correct formula for the density of X+Y, what you have there seems to be the formula for E[X+Y] imho

Yeah sorry I realized I made a mistake, and that link helped a lot. Thank you!
 
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