Finding kinetic energy and speed for a 0.600 kg particle

[Sheneron]

Homework Statement

A 0.600 kg particle has a speed of 2.30 m/s at point A and kinetic energy of 7.00 J at point B.

(a) What is its kinetic energy at A?
(b) What is its speed at B?
(c) What is the total work done on the particle as it moves from A to B?

Homework Equations

J= N*m

The Attempt at a Solution

I am stuck on this problem and don't really know how to go about starting it. I think if i new the first part I could find the other two answers, but I don't know how to do that. Any advice would be appreciated.

 

[cepheid]

What is the formula for kinetic energy?

 

[Sheneron]

k=.5mv^2

so, k=.5(.6)(2.3^2); k=1.59

b) 7=.5(.6)v^2; v=23.3333^.5; v=4.83

c) (sum)W= kf - ki ; (sum)W= 7-1.59 = 5.41

Thanks,
its been a long day sorry

 

[cepheid]

heh. no problem. It looks like you know EXACTLY what you are doing! =)