Finding limit of (2sin(x)−1)/(6x−π) as x→π/6

[Dick]

because you said that 2*cos(u)*sin(pi/6) is the cos(u) part.

Are you saying that you don't see why it is equal to cos(u)?

 

[mtayab1994]

Are you saying that you don't see why it is equal to cos(u)?

Is my answer of 1/(2√3) correct?

 

[Dick]

Is my answer of 1/(2√3) correct?

Yes, it is. That's the same thing l'Hopital would give you. You can always use l'Hopital to check these even if you can't use it to solve the problem.

 

[mtayab1994]

Yes, it is. That's the same thing l'Hopital would give you. You can always use l'Hopital to check these even if you can't use it to solve the problem.

Yes thank you, I really appreciate your help :) .