Finding Limits with a Constant: Tips for Calculus Students

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Homework Help Overview

The discussion revolves around finding the limit of a given expression involving a constant 'a' as 'h' approaches 0. This falls under the subject area of calculus, specifically limits and continuity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach the limit problem and seeks pointers. Some participants suggest substituting values and expanding the numerator as potential strategies. There is also a mention of confusion regarding continuity theorems.

Discussion Status

The discussion includes attempts to clarify the problem and explore different approaches. Some participants have provided guidance on expanding the expression, while others have shared their own results and reflections on understanding the limit.

Contextual Notes

The original poster notes feeling overwhelmed by the pace of the calculus class and mentions specific topics they have covered, such as the Intermediate Value Theorem and limit laws, which may influence their understanding of the problem.

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Homework Statement



Find in terms of the constant a

Lim h --- > 0

8 (a+h)² - 8a²
-----------------
h


The Attempt at a Solution



I have no idea how to even approach it so some pointers would be nice.
It hasn't been long since I started calculus. I am not sure weather we covered this
or not , classes are so heavy with content and passes quickly :s .

anyways what I am sure we have seen until now is

-IVT
- squeeze
- Limit laws

we have seen some things concerning continuity theorems altho am currently lost in them.
 
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Well,if you substitute in the value of h=0 directly, then you will get 0/h = 0.
So, why don't you try to expand the numerator? Then, proceed to the operations and eventually, the h at the denominator will be canceled out.
 
well I end up with 16a = something . am giong to look at it more
 
Last edited:
huh.. well the answer Is 16a altho I don't really understand it.
 
Ooo I get it now well thanks for your time.
 

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