Finding Local Max/Min of Complex Function

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To determine local maxima or minima of a complex function, one must consider the function's behavior in the complex plane. The example function f(z) = z * conjugate(z) simplifies to f(z) = x^2 + y^2, which is always nonnegative and has an absolute minimum at 0. The discussion highlights that while this specific function has a minimum, complex functions in general do not have a well-defined notion of maxima or minima due to the lack of an order in complex numbers. The graphical representation in R3 shows that the function forms a paraboloid, emphasizing its minimum value. Understanding these concepts is crucial for analyzing complex functions effectively.
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Homework Statement



How can i determine whether a complex function has any local maximum or minimum?

Homework Equations



let's consider the case f(z)=z* (conjugate of z)
z=x+iy

The Attempt at a Solution



f(z)=z*=x-iy

how do i see if it has local max or min?

Thank you
 
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f(z)~=~z\bar{z}~=~(x + iy)(x - iy)~=~x^2 + y^2
So f(z) is purely real, for any complex number z. It looks to me like it has an absolute minimum but no maximum.
 
how do you know it has an absolute minimum?
 
x and y are real numbers. Both x2 and y2 are always nonnegative, so their sum will also always be nonnegative.
 
i agree, but why does this have anything to do with max/min?
 
The minimum value of your f(z) is 0 and there is no maximum value. Are you asking about complex functions in general, or about this one?
 
im asking in general.
if we look at your example, f(z)=zz*
then why is there a minimum?
 
If you're asking in general, then you would be looking at the derivative and seeing where it's zero, and testing the critical points.

You're overthinking your example (it's not mine). You have f(z) = zz* = x2 + y2, where z = a + bi. For this particular function, it's very easy - almost trivial - to discover that the minimum value is 0 (for z = 0 + 0i), and that the function is unbounded. For any real numbers x and y, x2 \geq 0 and y2 \geq 0, which means that x2 + y2 \geq 0.

If you think about it graphically, the complex plane is the domain and the image of the function is a paraboloid that opens upward and whose vertex is at (0, 0).
 
oh, so the graph would be like y=x^2 in real coordinate system
?

how did you know that f=x^2+y^2 looks like that in the complex plane?
 
  • #10
sara_87 said:
oh, so the graph would be like y=x^2 in real coordinate system
?

how did you know that f=x^2+y^2 looks like that in the complex plane?
Not in the complex plane. The complex plane is the domain.
I know what it looks like because I know what the graph of z = x2 + y2 looks like in R3. The only thing different is that the domain in one of these is the complex plane and in the other it's the real x-y plane.
 
  • #11
ok, so it's in 3d. I get it now, so we have: z=x^2+y^2 not f(z)=x^2+y^2
right?
 
  • #12
In the original post, you asked "How can i determine whether a complex function has any local maximum or minimum?".

In general, the question doesn't make any sense because the complex numbers aren't ordered. Which is larger, 3 + 4i or 4 + 3i?

You have given a particular function that happens to have real values, which is why your particular problem makes sense.
 

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