Finding Lorentz Vector? -Physics Noob

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SUMMARY

The discussion focuses on calculating the Lorentz vector for muons resulting from a collision, specifically addressing the challenge of determining the z-component of momentum (Pz). The user has successfully calculated transverse momentum (Pt) using the equations Px = Pt cos(phi) and Py = Pt sin(phi). The key insight shared is that pseudorapidity (η) relates to the angle from the z-axis, and the user can derive the total momentum (P) from Pt and η using the formula η = -log(tan(θ/2)). Understanding these relationships is crucial for accurately finding the Lorentz vector.

PREREQUISITES
  • Understanding of Lorentz vectors in particle physics
  • Familiarity with transverse momentum (Pt) calculations
  • Knowledge of pseudorapidity (η) and its significance
  • Basic trigonometry and logarithmic functions
NEXT STEPS
  • Study the derivation of Lorentz vectors in particle physics
  • Learn about the relationship between pseudorapidity and momentum components
  • Explore the concept of rapidity and its applications in high-energy physics
  • Investigate advanced momentum conservation principles in particle collisions
USEFUL FOR

Undergraduate physics students, particle physicists, and anyone interested in understanding momentum calculations in high-energy collisions.

godtripp
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I was given this as an extra-curricular activity... way over my understanding of physics, sophmore year undergraduate.

But I can use a bit of help.
I'm given data from a collision resulting in 2 muons.

(this is exactly how the text is written to me, if any of these definitions are not exactly correct please note)

For a muon, we measure
"pt", Transverse momentum = sqrt (px^2 + py^2)
"phi", angle in the x-y plane
"eta", pseudorapidity, which is another form of the angle from the z-axis
"mass", the mass of the muon

I need to find the Lorentz vector.

For the energy I figured out
E = sqrt ( mass^2 + momentum^2) where momentum should be the magnitude of the 3vector momentum.

What I'm having trouble with is finding Pz, momentum in the z axis.
Maybe I'm not quite understanding the definition of pseudorapidity?

I'd find Px and Py by
Px=Pt cos(phi) and Py = Pt sin(phi)

But how do I find the z component of momentum?

psuedorapidity only gives me an angle for the z component correct? and am I correct that Ptransverse doesn't contain any z component?
 
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Hi godtripp! :smile:

(have a phi: φ and an eta: η and try using the X2 and X2 icons just above the Reply box :wink:)
godtripp said:
But how do I find the z component of momentum?

psuedorapidity only gives me an angle for the z component correct? and am I correct that Ptransverse doesn't contain any z component?


Yes, Pt is the component transverse to the z-direction, so it's only made up of Px and Py.

Pt = P.sinθ, where θ is the angle from the z-axis.

So you can get P (you don't need Pz) from Pt and η by using η = -logtan(θ/2) … see http://en.wikipedia.org/wiki/Pseudorapidity. :wink:
 
Thank you so much tim. I was thinking of the angle from psuedorapidity in terms of the Pz vector component and not of the total momentum! Thanks!
 

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