Finding M1 in a Mass Sliding Problem with an Angle and Friction

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Homework Help Overview

The problem involves two masses, M1 and M2, connected over a frictionless pulley, with M2 moving downwards. The objective is to find the mass M1 given specific parameters, including the acceleration of M2, the angle of inclination, and the coefficient of kinetic friction.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on both masses, breaking down the components of forces for M1 and setting up equations based on Newton's second law. Some participants question the correctness of the trigonometric functions used in the equations.

Discussion Status

Participants are actively engaging with the problem, with one confirming a realization of a mistake in the use of trigonometric functions. There is a collaborative atmosphere as participants provide feedback on each other's reasoning.

Contextual Notes

There is a reference to an image that is not displaying properly, which may affect the clarity of the problem setup. The discussion also hints at the complexity of the relationships between the forces involved.

Kpgabriel
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Homework Statement


M1 and M2 are two masses connected as shown.
https://loncapa2.physics.sc.edu/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob75_fricpullplane.gif
upload_2016-10-6_16-47-34.png

The pulley is light and frictionless. Find the mass M1, given that M2 (3.50 kg) is moving downwards and accelerates downwards at 2.99 m/s2, that θ is 20.0°, and that μk is 0.470.

Homework Equations


F = ma

The Attempt at a Solution


So I have broken down the components of the forces especially for M1 because the Mg force has the components sin and cos. I found the force in the y direction of M1 to be Fn=M1gSin(theta). Then I found the x direction to be T(tension)-u(friction)Fn-M1gCos(theta)=M1a. Which would make T= M1(ugSin(theta) + gCos(theta) +a). And for block 2 I have T = M2(g-a). Then I set the T's equal to each other and solve for M1 but it seems to be wrong.
 
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Your image isn't showing. No doubt an offsite link to some place that not publicly accessible. Try uploading it instead (use the UPLOAD button at the bottom right of the edit window).
 
Ok I think I got it
 

Attachments

  • phys_problem1.gif
    phys_problem1.gif
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Are you sure you haven't got ##\cos## and ##\sin## mixed up?
 
PeroK said:
Are you sure you haven't got ##\cos## and ##\sin## mixed up?
I did... Thank you so much!
 

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