Finding magnitude and distance of a particles acceleration

  • Thread starter Drub
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  • #1
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Homework Statement


The figure depicts the motion of a particle moving along an x axis with a constant acceleration. The figure's vertical scaling is set by xs = 7.20 m. What are the (a) magnitude and (b) direction of the particle's acceleration ( +x or -x )?

upload_2015-8-29_15-16-29.png


Homework Equations


upload_2015-8-29_15-16-55.png


The Attempt at a Solution


I'm going to be honest, first week into class and I'm struggling pretty hard. I'm not really sure where to begin with this equation to be honest.
 

Answers and Replies

  • #2
BvU
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Hello Drub, welcome to PF :smile: !

All beginnings are difficult (old duch saying). But perhaps PF can help you to get going !

If we start with the end of your post, as well as with the (b) part of the exercise: what do you think: is the particle being accelerated in the +x or in the -x direction ?
 
  • #3
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Thank you for your response :)! I believe it starts accelerating negatively, but then when it crosses the x axis it starts accelerating positively. am I on the right track here?
 
  • #4
BvU
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Actually, we might go one step back. Is it moving in the positive x-direction when it's moving from ##-1x_S## to ##0## from time 1 to 1 sec ?
 
  • #5
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I believe it is moving in the positive direction in that scenario :O?
 
  • #6
BvU
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Yes. And is its speed increasing or decreasing ?
 
  • #7
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Increasing :eek:?

EDIT: i worked with a friend on it and found out that I had to use the formula Deltax = Vi*T + .5(at^2) to solve for a. after i found that a= 2(xfinal - xinital)/t^2. I then plugged in values for 1-2, and got 4.8 m/2^2.

I didn't plug in 0 seeing as 0 would have just gotten me an acceleration of 0 since the particle was not moving.

Thanks for the reply, I'll be sure to be posting on here again as this is quite the challenge so far! :)
 
Last edited:
  • #8
BvU
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Increasing is good.
And working together is a good way to learn for both ! Good luck !
 

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