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Finding magnitude of a particle

  1. Oct 17, 2009 #1
    1. The problem statement, all variables and given/known data
    A magnet produces a 0.90 T field between its poles, directed to the east. A dust particle with charge q = -1.0 10-18 C is moving straight down at 0.70 cm/s in this field. What is the magnitude and direction of the magnetic force on the dust particle?


    2. Relevant equations

    f=qvb

    3. The attempt at a solution
    (1.0e-18)(.007)(.90)=-6.3e-21 which is wrong

    I followed the same format as someone else and my answer is wrong. can you help point out what the mistake is? thanks.
     
  2. jcsd
  3. Oct 17, 2009 #2

    berkeman

    User Avatar

    Staff: Mentor



    Your magnitude looks correct. What direction did you get via the right-hand rule?
     
  4. Oct 17, 2009 #3
    my direction is north
     
  5. Oct 17, 2009 #4
    never mind i figured out the answer. thanks for your help
     
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