Motion of a charged particle in magnetic field

In summary: Imagine placing your index finger perpendicular to the face of an analog clock and keeping it fixed. What is the angle between your finger and the seconds hand at any time t? The seconds hand is like the velocity vector that changes direction in the plane of the screen and your index finger is like the magnetic field the direction of which is fixed.0
  • #1
Abhimessi10
43
0

Homework Statement


A particle of charge -q and mass m enterd magnetic field B at A with speed v1 at an angle alpha and leaves the field at C with v2 at angle beta.Then,

a)alpha=beta
b)v1=v2
c)particle remains in the field for time t=(2m(pi-alpha))/qB
d)All of these

Please see image below

https://ibb.co/iLMrie

Abhimessi10fig.jpg

Homework Equations


F=qvB

The Attempt at a Solution


Really don't know how to do it.Tried resolving components.
 

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  • #2
Abhimessi10 said:

Homework Statement


A particle of charge -q and mass m enterd magnetic field B at A with speed v1 at an angle alpha and leaves the field at C with v2 at angle beta.Then,

a)alpha=beta
b)v1=v2
c)particle remains in the field for time t=(2m(pi-alpha))/qB
d)All of these

Please see image below

https://ibb.co/iLMrie

Homework Equations


F=qvB

The Attempt at a Solution


Really don't know how to do it.Tried resolving components.[/B]
Resolving components will not get you very far. Other than F=qvB, what else do you know about the motion of particles in magnetic fields? Can you draw the path connecting the entry and exit points of the particle?
 
  • #5
kuruman said:
Resolving components will not get you very far. Other than F=qvB, what else do you know about the motion of particles in magnetic fields? Can you draw the path connecting the entry and exit points of the particle?

I don't know to draw the path for particles entering at general angles.just the case when angle=90, 0, and in between.
 
  • #6
Abhimessi10 said:
I don't know to draw the path for particles entering at general angles.just the case when angle=90, 0, and in between.
OK. What kind of path do you get in these cases? Why is the path like that and like something else?
 
  • #7
kuruman said:
OK. What kind of path do you get in these cases? Why is the path like that and like something else?
Because of magnetic force acting as centripetal force?
 
  • #8
Abhimessi10 said:
Because of magnetic force acting as centripetal force?
Yes., and if the magnetic force is centripetal, what kind of path does the particle describe for as long as the force remains centripetal?
 
  • #9
kuruman said:
Yes., and if the magnetic force is centripetal, what kind of path does the particle describe for as long as the force remains centripetal?

Depends on the angle velocity makes with the magnetic field.On a general basis i can say circular-kinda motion.
 
  • #10
Abhimessi10 said:
Depends on the angle velocity makes with the magnetic field.On a general basis i can say circular-kinda motion.
Look at your drawing. The magnetic field is directed into the screen and the velocity vector is in the plane of the screen. What do you think the angle between the magnetic field and the velocity is?
 
  • #11
kuruman said:
Look at your drawing. The magnetic field is directed into the screen and the velocity vector is in the plane of the screen. What do you think the angle between the magnetic field and the velocity is?
The sin alpha component of velocity is only perpendicular
and cos alpha would remain same?
 
  • #12
Abhimessi10 said:
The sin alpha component of velocity is only perpendicular
Imagine placing your index finger perpendicular to the face of an analog clock and keeping it fixed. What is the angle between your finger and the seconds hand at any time t? The seconds hand is like the velocity vector that changes direction in the plane of the screen and your index finger is like the magnetic field the direction of which is fixed.
 

1. How does a charged particle move in a magnetic field?

When a charged particle, such as an electron, enters a magnetic field, it experiences a force perpendicular to both its velocity and the direction of the magnetic field. This force causes the particle to move in a circular or helical path, depending on the strength and direction of the magnetic field.

2. What is the equation for the motion of a charged particle in a magnetic field?

The equation for the motion of a charged particle in a magnetic field is known as the Lorentz force equation: F = q(v x B), where F is the force, q is the charge of the particle, v is its velocity, and B is the magnetic field strength. This equation describes the force acting on the particle and its resulting motion.

3. How does the speed of the charged particle affect its motion in a magnetic field?

The speed of the charged particle does not affect the path it takes in a magnetic field, but it does affect the radius of its circular or helical path. The faster the particle is moving, the larger the radius of its path will be.

4. What is the difference between a positively charged particle and a negatively charged particle in a magnetic field?

Positively charged particles, such as protons, experience a force in the opposite direction as negatively charged particles, such as electrons, in a magnetic field. This is due to the fact that the direction of the force is dependent on the charge of the particle, with like charges repelling each other and opposite charges attracting each other.

5. How do external factors, such as gravity, affect the motion of a charged particle in a magnetic field?

The motion of a charged particle in a magnetic field is not affected by external factors such as gravity, as the magnetic force is independent of these external forces. However, if the charged particle has a mass, it will still experience the effects of gravity, which may alter its path in addition to the magnetic force acting on it.

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