Finding mass of a sliding block

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SUMMARY

The problem involves calculating the mass of a block weighing 250N sliding down a 25m inclined plane at an angle of 36.9 degrees, with a coefficient of friction of 0.5. The correct approach to find the mass is to use the formula W = mg, where W is the weight and g is the acceleration due to gravity (10 m/s²). Therefore, the mass of the block is calculated as 250N / 10 m/s², resulting in a mass of 25 kg.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of weight and mass relationship (W = mg)
  • Basic trigonometry for angle calculations
  • Friction concepts, including coefficient of friction
NEXT STEPS
  • Study the principles of inclined planes in physics
  • Learn about the effects of friction on motion
  • Explore the calculation of forces on inclined surfaces
  • Investigate the relationship between weight and mass in different gravitational fields
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone looking to understand the dynamics of sliding objects on inclined planes.

KatieLynn
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Homework Statement



Assume g= 10 m/s^2
A plane 25m in length is inclined at an angle of 36.9 degrees. A block of weight 250N is placed at the top of the plane and allowed to slide down. The coefficient of friction is 0.5. The velocity is negative and the block weighs 250N. The mass of the block is most nearly what?

Homework Equations



i don't know...

The Attempt at a Solution



so 250N/sin(36.9)=416.37kg (?) is that anywhere near what I should be doing?
 
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Weight is given by W= mg. I'm not sure why this question has all the extra information unless there are several parts or you haven't typed it in full.
 

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