Finding Maximum kinetic energy of ejected electrons

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SUMMARY

The discussion focuses on calculating the maximum kinetic energy of ejected electrons from yellow light with a wavelength of 578 nm and a cutoff potential of 0.25 V. The relevant equation is E = hc/λ, where E represents the energy of the photons. Participants clarify that the total energy calculated using this equation does not directly yield kinetic energy, necessitating the consideration of the cutoff potential to find the maximum kinetic energy using the formula KE = E - eV.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with the equation E = hc/λ
  • Knowledge of kinetic energy calculations
  • Basic concepts of voltage and electron ejection
NEXT STEPS
  • Study the photoelectric effect in detail, focusing on energy calculations
  • Learn how to apply the formula KE = E - eV for kinetic energy determination
  • Explore the implications of cutoff potential on electron emission
  • Investigate the relationship between wavelength, frequency, and photon energy
USEFUL FOR

Students in physics, educators teaching the photoelectric effect, and anyone interested in quantum mechanics and energy calculations related to light and electrons.

pleace
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Homework Statement


So i know the light colour, wavelength, cutoff potential and frequencies. I am trying to find the maximum kinetic energy of the ejected electrons(J or eV)
heres the first set of numbers for the colour of yellow:
wavelength 578nm(5.78 x 10 to the -7metres). cutoff potential 0.25v. Frequency= 5.19 x 10 to the 14 HZ

Homework Equations


E= hc/λ


The Attempt at a Solution


so i started to think that i was supposed to use the equation e=hc/λ. but it is not getting me the right answer. i think this might be because the "E" is just total energy and not kinetic, but i have no idea what to do. Please help
 
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