Finding molar mass of unknown element

  • Thread starter Thread starter mjolnir80
  • Start date Start date
  • Tags Tags
    Element Mass
Click For Summary
SUMMARY

The discussion focuses on calculating the molar mass of an unknown element (X) that reacts with oxygen to form X2O3. Given that 1.0g of X produces 1.1596g of X2O3, the reaction can be represented as 4X + 3O2 → 2X2O3. The molar mass of X can be derived by determining the mass of oxygen involved in the reaction and using stoichiometric relationships. The key conclusion is that the molar mass of X can be calculated without needing the complete reaction equation.

PREREQUISITES
  • Understanding of stoichiometry and mole concept
  • Knowledge of chemical reactions and balancing equations
  • Familiarity with molar mass calculations
  • Basic algebra for solving equations
NEXT STEPS
  • Learn how to calculate moles from mass using the formula: moles = mass/molar mass
  • Study stoichiometric relationships in chemical reactions
  • Explore the concept of limiting reactants in chemical equations
  • Practice molar mass calculations for various compounds
USEFUL FOR

Chemistry students, educators, and anyone interested in mastering stoichiometry and molar mass calculations in chemical reactions.

mjolnir80
Messages
54
Reaction score
0

Homework Statement


element X reacts with oxygen to produce a pure sample of X2O3 . in an experiment, it is found that 1.0g of X produces 1.1596g of X2O3 . what is the molar mass of X?


Homework Equations





The Attempt at a Solution


well we can write a equation for it 4X + 3O2 ---> 2X2O3
from this we can see that 4 moles of X gives 2 moles of X2O3.
so 4*x(x is molar mass of X)g of X gives 2x+96 g of X2O3
where do we go from here?
 
Physics news on Phys.org
You don't need reaction equation to solve the question. Can you calculate number of moles of metal knowing number of moles of oxygen? Can you calculate mass of oxygen from the numbers given?
 

Similar threads

Replies
2
Views
4K
  • · Replies 14 ·
Replies
14
Views
12K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K