Finding molarity when % by mass is known

  • Thread starter Thread starter erjkism
  • Start date Start date
  • Tags Tags
    Mass Molarity
Click For Summary
SUMMARY

The discussion focuses on calculating the molarity of acetic acid (CH3COOH) given its percentage by mass (99.7%) and density (1.05 g/ml). To determine molarity, first calculate the mass of acetic acid in grams using the formula for density (d = m/v). Then, convert the mass to moles using its molar mass (60.05 g/mol) and apply the molarity formula (M = n/v), where n is the number of moles and v is the volume in liters.

PREREQUISITES
  • Understanding of molarity and its formula (M = n/v)
  • Knowledge of density and its relationship to mass and volume (d = m/v)
  • Familiarity with molar mass calculations
  • Basic skills in unit conversion (grams to moles)
NEXT STEPS
  • Learn how to calculate density and its implications in solution chemistry
  • Study the concept of molarity in detail, including examples and applications
  • Explore the conversion of mass to moles using different substances
  • Investigate the properties and uses of acetic acid in laboratory settings
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in solution preparation and concentration calculations.

erjkism
Messages
54
Reaction score
0
i need to find the molarity of acetic acid from this data:

CH3COOH (molar mass 60.05) (% by mass: 99.7) (density: 1.05 g/ml)

how do i do it??
 
Physics news on Phys.org
Find out the mass in grams of 99.7 % of the compound and d = m/v and M = n/v. Hope that helps.
 
One more thing that I want to add to the previous post is that after you find the mass you should convert it to moles and apply it to the molarity formula.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
Replies
2
Views
4K
Replies
7
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 14 ·
Replies
14
Views
12K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K