Density of Solution and mass percent

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Discussion Overview

The discussion revolves around the calculation of molarity for solutions, specifically comparing the approach for methanol and sulfuric acid (H2SO4). Participants explore the implications of density and mass percentage in determining molarity, raising questions about the differences in methodology for these two cases.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents two numerical problems involving the calculation of molarity, questioning why different formulas are used for methanol and H2SO4.
  • Another participant challenges the density value provided for H2SO4, suggesting it may be incorrect.
  • A participant proposes that the difference in approach may stem from the concentration of H2SO4 being 98% by mass, prompting a question about whether the density refers to the acid or the solution.
  • One participant suggests calculating the mass of a liter of solution and the mass of sulfuric acid within it to find moles, indicating a method for deriving molarity.
  • Another participant expresses confusion about the additional information provided by mass percentage and asks about the difference between solution strength and density.
  • Several participants discuss the conversion of mass to volume and moles, with one participant calculating the mass of sulfuric acid in a given mass of solution.
  • A participant notes that using a basis of 1 liter of solution simplifies the calculations compared to using 100 grams of solution.

Areas of Agreement / Disagreement

Participants express differing views on the methodology for calculating molarity, with no consensus reached on the best approach or the implications of using density versus mass percentage.

Contextual Notes

Some participants reference specific calculations and assumptions, such as the mass of the solution and the conversion between mass and volume, which may depend on the definitions used in the context of the discussion.

harman90
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There are two numericals,

1. Density of Methanol is 0.793 kg/l. Find molarity. ANSWER is : Desity/ Molar mass = Molarity (UNDERSTANDABLE)

In other numerical
2. Concentration of H2SO4 is 98% by mass having density of 1.84gm/ml. Calculate Molarity.
here they used another formula.

now my question is, How second question is different from First ? why didnt they took density and devided it by Molar mass to get molarity?
What I am missing?
 
Last edited:
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The density of your H2SO4 looks wrong to me.
 
Sorry ! Corrected. It was missing decimal.
 
I imagine the difference is in the concentration. If H2SO4 is 98% of the concentration by mass, is the 1.84gm/ml the density of H2SO4 or the density of the concentration?
Perhaps if you posted the formula you are looking at, it would make clear what the example is trying to show.
 
Take as a basis 1 liter of solution. What is the mass of this 1 liter of solution? If the mass fraction of sulfuric acid is 0.98, what is the mass of sulfuric acid in the 1 liter of solution? How many moles is that?

Chet
 
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Thank you guys for your reply.

Formula is MOLARITY = (%age * density *10)/ Density
 
Last edited:
Chestermiller said:
What is the mass of this 1 liter of solution? If the mass fraction of sulfuric acid is 0.98, what is the mass of sulfuric acid in the 1 liter of solution? How many moles is that?

Sorry I didnt get what you are implying.
Here is another way to Present my Doubt. We say that Molarity of Pure water is 55.5 ( which we calculate by using Density as 1)
Now By giving mass percentage, What extra information is given ?

SECOND: what is difference between STRENGTH of soln. and DENSITY of solution.
 
Giving you what?
 
Molarity

Well it is simple derivation, By considering mass of solution = 100gm and H2SO4 = 98gm
then they converted Mass of solution into VOLUME. and converted mass of H2SO4 into moles.
Once you have both of them, you can get molarity.

NOW my confusion is ... Why didnt they simply converted DENSITY ( gm/ml) Into Molarity ( MOLES/ ml)
what I am missing?
 
  • #10
Time to back up a couple steps; what is the definition of molarity?
 
  • #11
Moles in Litre Solution
 
  • #12
... and, if the density of 98% sulfuric acid is 1.84 g/cm3, one liter contains how many grams?
 
  • #13
I think I got it ?
If I only consider Density : 1 litres contain 1840 gm ,
Now this 1840gm will be of weight of (Sulphuric acid + water) ?
 
  • #14
harman90 said:
Now this 1840gm will be of weight of (Sulphuric acid + water) ?
Yes. How much sulfuric acid?
 
  • #15
Alright ...

SO 98gm H2SO4 in 100gm solution.
100 gm solution = 54.3 ml.

Weight of Sulphuric acid is = 98/54.3 * 1000 = 1804.8 gm
 
  • #16
Correct. That will be how many moles?
 
  • #17
18.4 moles

Thanks.
 
  • #18
This would all have been much simpler if you had chosen as a basis of the calculation 1 liter of solution rather than 100 gm of solution (as I suggested in post #5).
mass of 1 liter of solution = 1840 gm
mass of H2SO4 = (0.98)(1840)=1804.8 gm
moles of H2SO4 = 18.4
moles H2SO4 per liter of solution = 18.4

Chet
 

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