Finding Multiple Angles from Sine Values on the Unit Circle

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Homework Help Overview

The discussion revolves around finding multiple angles corresponding to sine values on the unit circle, specifically addressing the angles derived from given sine equations and their potential errors.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between sine values and angles, questioning the correctness of calculated angles and the methods used to derive them. There are discussions about potential typos in equations and the need for clarity in showing work step by step.

Discussion Status

The discussion is active, with participants providing guidance on how to approach finding multiple angles for a given sine value. There is an emphasis on understanding the relationships between angles and their sine values, though no consensus has been reached on the specific calculations.

Contextual Notes

Participants note potential typos in the equations presented and question the assumptions made regarding the angles derived from sine values. There is also mention of the need to consider angles within the range of 0 to 360 degrees.

Ethan
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Homework Statement
A straight wire 0.280 m in length carries a current of 3.40 A. What are the two angles between the direction of the current and the direction of a uniform 0.0400 T magnetic field for which the magnetic force on the wire has magnitude 0.0250 N?
Relevant Equations
F=ILBsin
I got 41 and correspondingly 49 from this. It said its wrong
 
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Please show your work.
 
0.025=3.4*.28*.04sinx sin^-1(0.025/0.3808)=41
 
I have no idea where you got that, but am sure 0.025 does not equal 41.

I recommend that you show your work step by step and only put numbers in at the end.
 
Vanadium 50 said:
I have no idea where you got that, but am sure 0.025 does not equal 41.
It was two separate equations.
Ethan said:
0.025=3.4*.28*.04sinx
sin^-1(0.025/0.3808)=41
The 0.3808 appears to be a typo for a tenth of that.
 
F5FB9864-C1A9-47E4-9F69-C707E5506768.jpeg
 
41o appears to be correct. But why did you choose the complementary angle (49o) for the second angle?

sin(41o) ≠ sin(49o)
 
cos^-1(0.6565) is 86.2 but that didn't work. How am I supposed to find a second angle?
 
Ethan said:
cos^-1(0.6565) is 86.2 but that didn't work. How am I supposed to find a second angle?
Draw two straight lines crossing. If one of the angles formed is x, what is the other?
Alternatively, if x=a is one solution of sin(x)=y, what is the other in the range 0 to 360?
 
  • #10
Ethan said:
cos^-1(0.6565) is 86.2 but that didn't work. How am I supposed to find a second angle?
You have shown that sinθ = .6565. So, you need to find two angles θ for which sinθ = .6565

You probably remember that sin(30o) = 0.5
Can you think of another angle whose sine is 0.5? What is the relation between the two angles?

Try this interactive unit circle. Click on the "Angles" button to display angles on the circle. As you move around on the circle, the length of the green line corresponds to the sine of the angle.
 
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