MHB Finding new limits of integration problem

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The discussion focuses on finding new limits of integration for two integral problems. In the first integral, the substitution leads to changing the bounds from 1 to infinity for x to -1 to -infinity for u, requiring a switch of bounds and multiplication by -1. The second integral involves a different substitution, where the bounds change from 0 to infinity for x to 1 to infinity for u, and there is no need to switch bounds or multiply by -1. The key takeaway is that the necessity to switch bounds and multiply by -1 depends on the specific substitution used. Understanding these rules is crucial for correctly evaluating integrals.
coolguy1
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In the integral

integral(1,infinity) e^(-sqrt(x)) / sqrt(x)

STEP 1:
I let u = -sqrt(x)
du = -1/(2sqrt(x))

then my lower bound u = -1
then my upper bound u = -infinity

-2 integral(-1,infinity) e^u du

I would then switch the order of the integration bounds and multiply by -1My question is in the next problem integral(0,infinity) x^2/(1+x^3) dx
I let u = 1 + x^3
du = 3x^2 dx
du/3 = x^2 dx

lower bound u = 1
upper bound u = infinity

My question is: Would you multiply by -1 and switch the lower and upper bounds in this problem, or was that just the case in the previous problem?Thanks for your help and sorry I'm new to the commands and not sure how to use them yet.
 
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In fact, it doesn't matter as long as you apply the rules correctly.
 
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