Finding Normal Vector for z=2e^(x+y)+8

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SUMMARY

The discussion centers on finding the normal vector for the surface defined by the equation z=2e^(x+y)+8. The user correctly derived the gradient vector, represented as ∇F=<2e^(x+y), 2e^(x+y), -1>. This gradient vector serves as the normal vector to the surface. The user also noted that the normal vector is not normalized and questioned the necessity of a unit normal vector, confirming the correctness of their calculations.

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Lancelot59
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I need to find the normal vector to:

[tex]z=2e^{(x+y)}+8[/tex]

So I did the following:

[tex]-8=2e^{(x+y)}-z[/tex]
[tex]\nabla F=<2e^{(x+y)},2e^{(x+y)},-1>[/tex]

Did I do this correctly?
 
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Although it's been a long time since I had this, I think yes. But it's not normalized, I don't know if you need a unit normal vector.
EDIT: Of course it's correct. Just struck me.
 

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