Finding parabola equation and only given a graph

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Homework Help Overview

The problem involves finding the equation of a parabola based on a provided graph. The original poster identifies the vertex of the parabola and expresses uncertainty about how to derive the equation from the graph.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to relate the vertex form of a parabola to the graph but is unsure how to apply it. Some participants suggest using the vertex form equation and provide guidance on isolating a variable based on known points.

Discussion Status

Participants are actively discussing the application of the vertex form of a parabola. Guidance has been offered regarding how to derive the equation, and there is an acknowledgment of the formula's applicability to parabolas with a vertical axis. However, there is no explicit consensus on the final equation.

Contextual Notes

The original poster has not provided specific numerical values from the graph, which may limit the discussion. There is also a mention of the timing of the responses, indicating a potentially informal atmosphere in the discussion.

stuffradio
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Homework Statement



The math problem I am supposed to do is, find an equation for the given graph.

Homework Equations


There are no equations given, but here's an image for it.
24gne5i.png



The Attempt at a Solution


I understand there is an equation like
y=ax^2+bx+c but I'm not sure how I can apply it to this graph. I know the Vertex of the Parabola is (0,5) and the line of symmetry I think it's called is x=0, but what I'm confused at is what the actual equation would be.

If anyone can give me a clue as how I can solve it, that would be great!
 
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Put it in vertex form [tex]y = a(x + h)^2 + k[/tex] where h is the x value of the vertex and k is the y value. The answer should then be [tex]y = ax^2 + 5[/tex], you can solve for a by plugging in values of x, y and then isolate a, there is a clear one [tex](1, 4)[/tex]. I don't know if I can give this much information though.
 
Wow, I'm impressed this was answered so quickly! Thanks!
So is this a standard equation that can be used for solving all parabola's?
 
stuffradio said:
Wow, I'm impressed this was answered so quickly! Thanks!
So is this a standard equation that can be used for solving all parabola's?
Especially at 1 AM!:wink:

Yes, that formula is true for all parabolas with vertical axis.
 

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