I Finding position vector in general local basis

Click For Summary
To derive the position vector in a general local basis, one must reference the specific coordinate system being used, such as spherical coordinates, where the position vector is expressed as **r** = r **e_r**. This expression highlights that **r** is the distance from the origin, and **e_r** is the unit vector pointing towards the point in question. The derivation relies on the definitions inherent to the coordinate system. In contrast, when using a global Cartesian basis, it's possible to express Cartesian coordinates and basis vectors in terms of curvilinear coordinates. Understanding these relationships is crucial for accurately representing vectors in different coordinate systems.
farfromdaijoubu
Messages
8
Reaction score
2
How do you derive the position vector in a general local basis?

For example, in spherical coordinates, it's ##\vec r =r \hat {\mathbf e_r}##, not an expression that involves that involves the vectors ## {\hat {\mathbf e_{\theta}}}## and ## \hat {{\mathbf e_{\phi}}}##. But how would you show this?
 
Physics news on Phys.org
This follows from the definition of the coordinate system. For example, in spherical polar coordinates, r is by definition the distance of a point from the origin and \mathbf{e}_r(\theta,\phi) is the unit vector in the direction of that point. Hence \mathbf{r} = r\mathbf{e}_r(\theta,\phi).

Otherwise, if you have a global Cartesian basis then you can express the cartesian coordinates and basis vectors in terms of the curvilinear coordinates and basis vectors.
 
  • Like
Likes farfromdaijoubu, SammyS and PeroK

Similar threads