Finding potential at a point in capacitor

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SUMMARY

The discussion focuses on calculating electrical potential at specific points in a circuit involving capacitors and resistors. The user successfully applied Kirchhoff's law to determine a current of 1.82 A and seeks clarification on using either 4.4Ω or 8.8Ω for resistance in Ohm's law to find voltage at point A. For point B, the user is uncertain whether to use 0.48 µF or 0.36 µF for capacitance in the equation Vb = Q/c. The concept of a potential divider is also introduced, emphasizing the relationship between resistance and voltage across components.

PREREQUISITES
  • Understanding of Kirchhoff's laws
  • Proficiency in Ohm's law
  • Knowledge of capacitance and equivalent capacitance (Ceq)
  • Familiarity with potential dividers in electrical circuits
NEXT STEPS
  • Study the application of Kirchhoff's laws in complex circuits
  • Learn about the calculation of equivalent capacitance in series and parallel configurations
  • Explore the concept of potential dividers and their applications in circuit design
  • Investigate the effects of different resistor and capacitor values on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in understanding the principles of voltage, current, and capacitance in electrical circuits.

Sunwoo Bae
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Homework Statement
shown below
Relevant Equations
Ohm's law, Kirchhoff law,
1644237234303.png


I tried solving the part (a), and got I =1.82 A for the current value using Kirchoff's law.
Next, I want to use Ohm's law to calculate the voltage at point a.
Va = IR
In this equation, will resistance R correspond to 4.4Ω or 8.8Ω?
How do you determine which resistance to use when solving this problem?

As for part B, I was able to calculate Ceq and Q through following works:
1644242333552.png


I am now trying to find the potential at point b with the switch open through equation
Vb = Q/c
Again, which value of capacitance, 0.48 µF or 0.36 µF, and why?

Thank you!
 
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Have you come across the idea of a potential divider? The voltage across either resistors is in proportion to the value of the resistance. The same idea carries across for the capacitors, except the weights are the reciprocals ##1/C##. Can you show why this is true?
 
Sunwoo Bae said:
Homework Statement:: shown below
Relevant Equations:: Ohm's law, Kirchhoff law,

View attachment 296733

I tried solving the part (a), and got I =1.82 A for the current value using Kirchoff's law.
Next, I want to use Ohm's law to calculate the voltage at point a.
Va = IR
In this equation, will resistance R correspond to 4.4Ω or 8.8Ω?
How do you determine which resistance to use when solving this problem?

As for part B, I was able to calculate Ceq and Q through following works:
View attachment 296735

I am now trying to find the potential at point b with the switch open through equation
Vb = Q/c
Again, which value of capacitance, 0.48 µF or 0.36 µF, and why?

Thank you!
You can use either resistor value.

You can use either capacitor value.

The problem states to use a potential value of 0 V at the negative terminal of the source.
What is the potential value at the positive terminal?
 

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