The original problem has very confusing wording without the picture so I reworded it for simplicity: A toy cannon is placed on a ramp on a hill, pointing up the hill. With respect to the x-axis the hill has a slope of angle A and the ramp has a slope of angle B. If the cannonball has a muzzle speed of v, show that the range R of the cannonball (as measured up the hill, not along the x-axis) is given by: R = [2v^2 (cos^2 (B))(tan(B) - tan(A))] / [g cos(A)] The base equation we've derived for projectile range on a flat surface: R = (v^2 /g)sin(2θ) from the parabolic equation: y = vt + (1/2)at^2 (where v is initial velocity, and v and a are in the y-direction) and setting y to 0. I'm not completely sure how to correctly start this problem or how to properly take the angle of the slope of the hill into account, the trig is a bit overwhelming. Even a good shove in the right direction would help immensely!