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Finding Q1 and Q2 in coulombs law

  1. Jun 17, 2012 #1
    0.36=(K)x(Q1xQ2/0.25^2)

    Find Q1 and Q2 if Q1=3(Q2)

    Using the solve function in my calculator I get Q1=2.74x10^-6 and Q2=9.13x10^-7

    I would just like to know whether my answer is correct and how to do it in a calculator without using the solve function.

    Thanks in advance.

    Edit: Yep sorry, missed out r :P
     
    Last edited: Jun 17, 2012
  2. jcsd
  3. Jun 17, 2012 #2
    You need the value of r to solve the equation.
     
  4. Jun 17, 2012 #3

    tiny-tim

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    Hi D.J Falcon! :smile:

    If Q1=3(Q2), then (K)x(Q1xQ2/0.252) = (K)x(3Q2xQ2/0.252) :wink:
     
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