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dragonfall122
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Homework Statement
block 1 with mass of 680 g starts from rest at the top of a frictionless track at a height of
H = 4.20 M above the ground. Block 1 collides with block 2 (m = 175 g) at ground level. The blocks stick together and barely complete one turn around a frictionless loop. find the radius of the loop.
Homework Equations
p = mv
mg = mv2/r
Ui + Ki = Uf + Kf
J1 + J2 = 0
The Attempt at a Solution
I found the velocity of block 1 using conservation of evergy,
Ui + Ki = Uf + Kf
Ki = 0 because the object is at rest and and Uf = 0 because the object is at height = 0, so
Ui = Kf
so mgh = 1/2mv^2 so V = 9.07 m/s before the collision.
I used that velocity to find it's momentum,
p=mv so p= (.680 kg)(9.07 m/s)
so p is 6.17 kgm/s immediately before the collision.
I know that at the top of the loop the normal force working on the two objects is zero, and a FBD shows that the sum of the forces working in the y direction are mg = mv2/r
I know that block 2 has no impulse or momentum before the collision because its at rest.
I know that somehow I'm supposed to find the velocity of the two blocks after the collision, but I don't know how.
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