Finding radius of satellite in orbit given mass and rotational period

Click For Summary
SUMMARY

The discussion focuses on calculating the radius of a satellite in geosynchronous orbit around Planet X, which has a mass of 5.90 x 1024 kg and a rotational period of 26.4 hours. The correct formula used is T2/r3 = 4π2/GM, leading to the rearranged equation r = (GMT2 / 4π2)1/3. After substituting the gravitational constant G = 6.67 x 10-11 m3kg-1s-2, the mass M, and the period T converted to seconds (95040 s), the calculated radius is 2.06 x 108 m or 2.06 x 105 km. The user expressed confusion over discrepancies in the calculations, indicating potential arithmetic errors.

PREREQUISITES
  • Understanding of gravitational constant (G) and its application in orbital mechanics
  • Familiarity with the law of periods in celestial mechanics
  • Ability to convert time units from hours to seconds
  • Basic proficiency in algebra for rearranging equations
NEXT STEPS
  • Study the derivation of Kepler's laws of planetary motion
  • Learn about the implications of geosynchronous vs. geostationary orbits
  • Explore the calculation of orbital speed using the formula v = √(GM/r)
  • Investigate the effects of mass and distance on gravitational force
USEFUL FOR

Astronomy students, physics enthusiasts, and aerospace engineers interested in orbital mechanics and satellite placement calculations.

csgirl504
Messages
18
Reaction score
0

Homework Statement



Suppose that Captain Omega of the Imperial Space Patrol wishes to place a spy satellite in geosynchronous orbit above the mysterious Planet X, which has a mass of 5.90 x1024 kg, and a rotational period of 26.4 hours.

(a) What should be the radius of the satellite's orbit?
(b) What would be the orbital speed of the satellite?

Homework Equations


The Attempt at a Solution



I used the law of periods : T2/r3 = 4∏2/GM

So I rearranged that to get:

r = (GMT2 / 4∏2) 1/3

I plugged in:
G = 6.67 e -11
M = 5.9 e 24 kg
T = 95040s

I ended up with 2.06e8 m = 2.06e5 km

But that answer isn't right and I don't understand what I'm doing wrong.
 
Physics news on Phys.org
I plug in your numbers to your formula and I get a different answer. You must have forgot a step in your arithmetic.
 
Thank you! I'm not sure what I was doing wrong..mistake while entering in the calculator I guess!
 

Similar threads

Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
10
Views
2K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
13
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K