The discussion focuses on calculating the recoil speed of a rifle when a bullet is fired, utilizing the principles of conservation of momentum. A rifle weighing 25 N fires a 5.5 g bullet at a speed of 260 m/s. The key equations used are momentum conservation equations, specifically m1v1i + m2v2i = m1v1f + m2v2f. Participants clarify the conversion of bullet mass from grams to kilograms and emphasize the importance of identifying the mass of the rifle from its weight.
PREREQUISITESPhysics students, educators, and anyone interested in understanding the mechanics of firearms and recoil dynamics.
Yep. That's all you need to solve both parts.mandy9008 said:momentum?
Sure. What's the initial velocity and momentum before the rifle is fired?mandy9008 said:m1v1i + m2v2i = m1v1f + m2v2f
Right. Keep going. You're given the final speed of the bullet.mandy9008 said:velocity and momentum is 0
Mass 2 is the mass of the rifle (at least in part a). You'll have to figure that out from the given information.mandy9008 said:okay, so it will be
mass 1 is 0.0055kg? then what is mass 2?
mandy9008 said:okay, so
m1v1i + (0.0055 kg) (0 m/s) = m1v1f + (0.0055 kg) (260 m/s)
I am confused now
You switched them around. You have m2 as the mass of the bullet, which means that m1 is the mass of the rifle (for part a). That's fine.mandy9008 said:okay, so
m1v1i + (0.0055 kg) (0 m/s) = m1v1f + (0.0055 kg) (260 m/s)
I am confused now