Finding recoil speed given force, mass, and velocity

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Homework Help Overview

The problem involves a rifle firing a bullet and requires finding the recoil speed of both the rifle and a man holding it. The subject area includes concepts of momentum and forces in mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of momentum as a key principle. There are attempts to clarify the initial conditions and the relationship between the masses of the bullet and the rifle. Questions arise about converting weight to mass and identifying initial velocities.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on how to approach the problem. There is a focus on writing out equations and understanding the implications of initial conditions. Some participants express confusion regarding the setup and calculations.

Contextual Notes

Participants note the need to convert the weight of the rifle to mass and clarify the initial velocities of the system. There is an emphasis on ensuring all variables are correctly identified before proceeding with calculations.

mandy9008
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Homework Statement


A rifle with a weight of 25 N fires a 5.5 g bullet with a speed of 260 m/s.
(a) Find the recoil speed of the rifle.
(b) If a 725 N man holds the rifle firmly against his shoulder, find the recoil speed of the man and rifle.


Homework Equations


p=mv
F=p/t


The Attempt at a Solution


I do not even know where to begin converting the mass to 0.0055 kg
 
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Hint: What's conserved as the rifle is fired?
 
momentum?
 
mandy9008 said:
momentum?
Yep. That's all you need to solve both parts.
 
m1v1i + m2v2i = m1v1f + m2v2f
 
mandy9008 said:
m1v1i + m2v2i = m1v1f + m2v2f
Sure. What's the initial velocity and momentum before the rifle is fired?
 
velocity and momentum is 0
 
mandy9008 said:
velocity and momentum is 0
Right. Keep going. You're given the final speed of the bullet.
 
okay, so it will be
mass 1 is 0.0055kg? then what is mass 2?
 
  • #10
mandy9008 said:
okay, so it will be
mass 1 is 0.0055kg? then what is mass 2?
Mass 2 is the mass of the rifle (at least in part a). You'll have to figure that out from the given information.
 
  • #11
okay, so
m1v1i + (0.0055 kg) (0 m/s) = m1v1f + (0.0055 kg) (260 m/s)

I am confused now
 
  • #12
mandy9008 said:
okay, so
m1v1i + (0.0055 kg) (0 m/s) = m1v1f + (0.0055 kg) (260 m/s)

I am confused now

You know weight of the rifle. Find mass of the rifle.
Before firing, rifle and bullet haven't moved yet. You can consider their velocities before firing.
 
  • #13
I suggest you write out all your equations and develop them before putting numbers in. Things are less messy then and thus more elegant.
 
  • #14
mandy9008 said:
okay, so
m1v1i + (0.0055 kg) (0 m/s) = m1v1f + (0.0055 kg) (260 m/s)

I am confused now
You switched them around. You have m2 as the mass of the bullet, which means that m1 is the mass of the rifle (for part a). That's fine.

You are given the weight of the rifle in Newtons, so what's its mass?

Since the initial speed of everything is zero, what does that do to the left hand side of your equation?
 

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