Finding secant with calculator

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The discussion focuses on calculating secant values, specifically sec(π/4) and sec(0). It clarifies that cos^-1 and acos are not the same as sec, as the latter is the reciprocal of cosine. The confusion arises from interpreting sec(π/4) as √2, while it is actually 2/√2, which simplifies to √2, confirming both the book and the user's calculations are correct. The participants emphasize that different representations of the same value can lead to misunderstandings, but ultimately, they agree on the equivalence of the results. Understanding these relationships is crucial for accurate calculations in trigonometry.
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Homework Statement



what is sec(pi/4)
what is sec(0)



The Attempt at a Solution



First let me make sure that cos^-1, acos and sec, they are all the same right?

I put in cos^-1(pi/4) in my calculator and the answer I get is .667, which I think is the same as sec (pi/4). The book says the answer is √2
 
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bobsmith76 said:

Homework Statement



what is sec(pi/4)
what is sec(0)

The Attempt at a Solution



First let me make sure that cos^-1, acos and sec, they are all the same right?
No! They are not the same. The first two, cos-1 and acos (do you mean arccosine?) are the inverse cosine functions. Put it simply, if cos(π/6) = √3/2, then cos-1(√3/2) = π/6.

You are confusing these with secant, which is the reciprocal of cosine. In order to evaluate secant on the calculator, you need to type
1/cos(your angle).
 
But I still don't see why sec(pi/4) is √2, it should be 2/√2 and my book clearly says it's √2
 
Since √2 * √2 = 2, then 2/√2 = √2 .
 
That doesn't make sense. cos (pi/4) = √2/2. If you take the inverse, which is the secant, then it's 2/√2, not sqaure root of 2
 
You could do the following subtraction:
\displaystyle \sqrt{2}-\frac{2}{\sqrt{2}}​
The answer is zero.

Or the following multiplication:
\displaystyle \frac{\sqrt{2}}{1}\cdot\frac{\sqrt{2}}{\sqrt{2}}
 
Sammy, all that gives 2√2, the book clearly says otherwise

Screenshot2012-02-02at53653PM.png
 
What we're trying to tell you is that 2/√2 and √2 are just different ways of writing the same number. They are equal. They are the same. You and the book are both right.
 
bobsmith76 said:
Sammy, all that gives 2√2, the book clearly says otherwise
Actually, neither one gives 2√(2) .

\displaystyle \sqrt{2}-\frac{2}{\sqrt{2}}=\frac{\sqrt{2}\sqrt{2}}{\sqrt{2}}-\frac{2}{\sqrt{2}}=\frac{2}{\sqrt{2}}-\frac{2}{\sqrt{2}}=0

\displaystyle \frac{\sqrt{2}}{1}\cdot\frac{\sqrt{2}}{\sqrt{2}}= \frac{\sqrt{2}\sqrt{2}}{\sqrt{2}}=\frac{2}{\sqrt{2}}

Screenshot2012-02-02at53653PM.png
⟵ This is correct !
 
  • #10
o, don't I feel stupid. thanks
 

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