Finding secant with calculator

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Homework Statement



what is sec(pi/4)
what is sec(0)



The Attempt at a Solution



First let me make sure that cos^-1, acos and sec, they are all the same right?

I put in cos^-1(pi/4) in my calculator and the answer I get is .667, which I think is the same as sec (pi/4). The book says the answer is √2
 
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bobsmith76 said:

Homework Statement



what is sec(pi/4)
what is sec(0)

The Attempt at a Solution



First let me make sure that cos^-1, acos and sec, they are all the same right?
No! They are not the same. The first two, cos-1 and acos (do you mean arccosine?) are the inverse cosine functions. Put it simply, if cos(π/6) = √3/2, then cos-1(√3/2) = π/6.

You are confusing these with secant, which is the reciprocal of cosine. In order to evaluate secant on the calculator, you need to type
1/cos(your angle).
 
But I still don't see why sec(pi/4) is √2, it should be 2/√2 and my book clearly says it's √2
 
That doesn't make sense. cos (pi/4) = √2/2. If you take the inverse, which is the secant, then it's 2/√2, not sqaure root of 2
 
Sammy, all that gives 2√2, the book clearly says otherwise

Screenshot2012-02-02at53653PM.png
 
What we're trying to tell you is that 2/√2 and √2 are just different ways of writing the same number. They are equal. They are the same. You and the book are both right.
 
bobsmith76 said:
Sammy, all that gives 2√2, the book clearly says otherwise
Actually, neither one gives 2√(2) .

[itex]\displaystyle \sqrt{2}-\frac{2}{\sqrt{2}}=\frac{\sqrt{2}\sqrt{2}}{\sqrt{2}}-\frac{2}{\sqrt{2}}=\frac{2}{\sqrt{2}}-\frac{2}{\sqrt{2}}=0[/itex]

[itex]\displaystyle \frac{\sqrt{2}}{1}\cdot\frac{\sqrt{2}}{\sqrt{2}}= \frac{\sqrt{2}\sqrt{2}}{\sqrt{2}}=\frac{2}{\sqrt{2}}[/itex]

Screenshot2012-02-02at53653PM.png
⟵ This is correct !
 
o, don't I feel stupid. thanks