Finding \sum_{n=1}^{\infty} (-1)^n/n - Homework Help

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seanhbailey
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Homework Statement


What is [tex]\sum_{n=1}^{\infty} (-1)^n/n[/tex]


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The Attempt at a Solution


I know that the alternating series [tex]\sum_{n=1}^{\infty} (-1)^{n-1}/n[/tex] converges to ln(2), but I am not sure how to find this series.
 
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(-1)n-1 = (-1)n(-1)-1 = -1*(-1)n
then you can take the constant -1 outside the sum.