Finding tangential speed to maintain an angle theta

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SUMMARY

The discussion focuses on calculating the tangential speed, v, required for a pendulum bob to maintain a horizontal circular motion while the string makes an angle theta with the vertical. The key equations derived include T = mg/cos(theta) for tension, r = Lsin(theta) for radius, and a_c = v^2/Lsin(theta) for centripetal acceleration. The horizontal inward radial force is expressed as mgtan(theta). The speed is determined to be v = sqrt[Lgsin(theta)tan(theta)], and the circumference for one full revolution is given by 2*pi*Lsin(theta).

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Linus Pauling
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1.
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What tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always making an angle theta from the vertical?
Express your answer in terms of some or all of the variables m, L, and theta, as well as the acceleration due to gravity g.




2. I figured out the following:

T = mg/cos(theta)
r = Lsin(theta)
a_c = v^2/Lsin(theta)




3. see above

I next had to get the horizontal (inward radial) force, which is mgtan(theta). How was that force obtained? Also, how do I use this information to answer the question?
 
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Second part of question: How long does it take the bob to make one full revolution (one complete trip around the circle)?

I know that the speed is constant = sqrt[Lgsin(theta)tan(theta), and I also know the distance is the circumference of the circle = 2*pi*Lsin(theta). I know I have to use kinematics but which equation?
 

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