- #1
Searay330
- 20
- 1
Suppose a wire made from an unknown alloy and having a temperature of 20.0°C carries a current of 0.529 A. At 52.4°C the current is 0.378 A for the same potential difference. Find the temperature coefficient of resistivity of the alloy.
tempinital = 20C
tempfinal = 52.4C
currentInital = .529A
currentFinal = .378A
Voltage = constant but unknownhow do you go about this problem i have tried manipulating ohms law ( I= V/R ) to remove voltage but that always leaves me with IR= IR.
TCOR = temperature coefficient of resistivity;
because the resistance isn't a constant i can't factor it out of RF = RI (1 - TCOR(TF - TI))
i can't use either form because i don't have resistance to solve for resistivity.
if someone could point me in the right direction that would be great.
tempinital = 20C
tempfinal = 52.4C
currentInital = .529A
currentFinal = .378A
Voltage = constant but unknownhow do you go about this problem i have tried manipulating ohms law ( I= V/R ) to remove voltage but that always leaves me with IR= IR.
TCOR = temperature coefficient of resistivity;
because the resistance isn't a constant i can't factor it out of RF = RI (1 - TCOR(TF - TI))
i can't use either form because i don't have resistance to solve for resistivity.
if someone could point me in the right direction that would be great.