MHB Finding Temperature in a Rectangular Plate: $\nabla^2u=0$

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The discussion focuses on finding the steady state temperature distribution $u(x,y)$ in a rectangular plate governed by the equation $\nabla^2u = 0$. The boundary conditions specify that one edge is held at zero degrees, another varies linearly with $y$, and the vertical edges are insulated. There is a clarification regarding the implications of insulated boundaries, emphasizing that while the temperature derivatives at those boundaries are zero, it does not imply that the Fourier coefficients themselves are zero. The conversation highlights the distinction between boundary conditions and the resulting mathematical implications for solving the differential equation. This nuanced understanding is crucial for accurately modeling the temperature distribution in the plate.
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The steady state temperature $u(x,y)$ in a rectangular plate $0\leq x\leq L$, $0\leq y\leq M$, is sought, under the condition that the edge $x = 0$ is maintained at zero degrees, $x = L$ is kept at $u(L,y) = y$ degrees, and the edges $y = 0$ and $y = M$ are insulated. The appropriate differential equation $\nabla^2u = 0$.

Since the vertical boundary conditions are insulated, wouldn't this be the same as just dealing with $u_t=u_{xx}$ since Fourier coefficients for those boundaries will be 0?
 
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Saying that the boundaries are insulated does NOT mean that the Fourier coefficients are 0. It means that the derivatives there are 0 and so the coefficients of the sine terms are 0.
 
Wasn't thinking figured out this post.
 
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