Calculating Tension in a Pulley System at an Angle

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SUMMARY

The discussion focuses on calculating tension in a pulley system at an angle, specifically using the equation T = mB1 * a, where T represents tension, mB1 is the mass of block B1, and a is the acceleration derived from the equation a = (F - cos(36.1)g). The calculated tension is 128 N. Participants emphasize the importance of free-body diagrams for each block and the need to clarify the orientation of the slope and the direction of the pulling force.

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  • Familiarity with free-body diagrams
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Homework Statement
A 1.7kg book B2 is connected by a rope and pulley to a 6.3kg book B1.
We neglect friction.
B2 is on a horizontal surface, and B1 is on a 36.1º slope.
If the force pulling B1 is 28.2N what is the tension between the two books?
Relevant Equations
T=gm
Hi!
I really can't figure this one out...
I have a = (F-cos(36.1)g) = a and from that I get T = mB1 a = 6.3 (20.3736) = 128 N.
Could someone please help?
Thanks!
 
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You need two equations that you get by drawing two free-body diagrams, one for each block. Is the slope above or below the horizontal? Is the pulling force parallel to the surface on which B2 slides? Please post a diagram.
 
Last edited:
Where is the pulley? Please show a picture of the complete setup as was given to you.
 
Screen Shot 2021-09-28 at 7.06.33 PM.png
 
Thank you for the drawing. There is tension T acting on B2 in a direction opposite to F, no? Ideal pulleys change the direction of the force but not its magnitude. Also, check the components of the weight in your equation for B2.
 

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