Finding tension force and and components of a uniform boom

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SUMMARY

The discussion focuses on calculating the tension force in a support cable and the components of the reaction force for a 1200-N uniform boom positioned at an angle of 55° to the horizontal, with a 2000-N weight hanging from its top. The problem utilizes fundamental equations of static equilibrium, specifically the torque equation (τ=Fd) and the sum of forces in both horizontal (ƩF_x=0) and vertical (ƩF_y=0) directions. Participants emphasize the importance of accurately representing forces in a free-body diagram to solve for the unknown tension and reaction forces effectively.

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kurispice
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Homework Statement



A 1200-N uniform boom at ∅=55° to the horizontal is supported by a cable at an angle θ=25.0° to the horizontal. The boom is pivoted at the bottom and an object of weight 2 000 N hangs from its top.
Find (a) the tension in the support cable and (b) the horizontal and vertical components of the reaction force exerted by the pivot boom.

Homework Equations



\tau=Fd
ƩF_{}x=0
ƩF_{}y=0

The Attempt at a Solution



What I did was start by drawing a diagram of the picture but I don't know how to draw in the force. Your help is appreciated!
 
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welcome to pf!

hi kurispice! welcome to pf! :smile:
kurispice said:
A 1200-N uniform boom at ∅=55° to the horizontal is supported by a cable at an angle θ=25.0° to the horizontal. The boom is pivoted at the bottom and an object of weight 2 000 N hangs from its top.

… I don't know how to draw in the force.

"cable" (like "rope" or "string", but unlike "beam" "boom" etc) means that the force must be along the cable :wink:
 

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