Find the tension in the horizontal cable that supports the boom

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SUMMARY

The discussion focuses on calculating the tension in the horizontal cable supporting a crane boom in a marble quarry. The crane supports a 2000 kg slab of marble, while the boom itself weighs 900 kg and is 15 meters long, with its center of mass located one-third from the pivot. The net torque around the pivot point is set to zero, and the torque calculation involves the weight of the boom and the slab, along with the angle of inclination. The solution requires organizing the torque equation to isolate the tension variable.

PREREQUISITES
  • Understanding of torque and its calculation in static equilibrium
  • Familiarity with basic physics concepts such as weight and center of mass
  • Knowledge of trigonometric functions, specifically cosine
  • Ability to analyze forces acting on a rigid body
NEXT STEPS
  • Study the principles of static equilibrium in mechanics
  • Learn how to calculate torque about different pivot points
  • Explore the application of trigonometric functions in physics problems
  • Investigate real-world applications of crane mechanics and load distribution
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and professionals involved in crane operation and structural analysis, particularly those focusing on load management and torque calculations.

k31453
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Homework Statement



A crane in a marble quarry is mounted on the rock walls of the quarry and is supporting a 2000 kg slab of marble as shown in the figure. The center of mass of the 900 kg boom is located one-third of the way from the pivot end of its 15-m length, as shown.



Given diagram: http://i38.tinypic.com/oqaltx.jpg

Homework Equations



a)Find the tension in the horizontal cable that supports the boom.

The Attempt at a Solution




net torque will be = 0,

at CM the torque will be 1/3 of length X 830 * 9.8 X cos50 ..

but i can't organize it for tension T
 
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k31453 said:

Homework Statement



A crane in a marble quarry is mounted on the rock walls of the quarry and is supporting a 2000 kg slab of marble as shown in the figure. The center of mass of the 900 kg boom is located one-third of the way from the pivot end of its 15-m length, as shown.



Given diagram: http://i38.tinypic.com/oqaltx.jpg

Homework Equations



a)Find the tension in the horizontal cable that supports the boom.

The Attempt at a Solution




net torque will be = 0,

at CM the torque will be 1/3 of length X 830 * 9.8 X cos50 ..

but i can't organize it for tension T

It will be easier to solve this problem by considering the torque about the pivot point of the crane -- at the crane's base.

attachment.php?attachmentid=64235&stc=1&d=1385269638.jpg
 

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