Finding the angle of a falling person on a sphere

Click For Summary

Homework Help Overview

The problem involves a skier standing on top of a sphere and seeks to determine the angle at which the skier will slide off when moving from rest to a constant velocity, considering the effects of gravity and centripetal force.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the role of centripetal force in the context of the skier's motion and question the assumptions regarding forces acting on the skier as they move along the sphere.

Discussion Status

Some participants have provided insights into the forces involved, while others have expressed confusion regarding the initial setup and the teacher's feedback. There appears to be a lack of consensus on the interpretation of forces acting on the skier.

Contextual Notes

Participants note discrepancies in the problem statement and the teacher's evaluation, leading to further exploration of the physics involved.

Enderless
Messages
4
Reaction score
0

Homework Statement



A sphere is on the ground, with the sphere having a radius R. A person (skier) is standing on top of the sphere. neglecting friction, find the angle at which the person will slide off the sphere if he moves from rest to a constant velocity of v.

http://img63.imageshack.us/img63/930/untitledai7.jpg

Homework Equations



F = ma
F = mv^2/r (centripetal force)
U + K = U + K (conservation of energy)


The Attempt at a Solution



1/2mv^2 + mgh = 1/2mv^2 + mgh
0J + m(9.8m/s^2)(2R) = 1/2mv^2 + m(9.8m/s^2)(R + Rcos (angle))

So that simplifies to v^2/2 = 9.8 m/s(R) - 9.8m/s(Rcos (angle))

Drawing a free body diagram, I know that the centripetal force is equal to the Normal foce*cos(angle):

mv^2/r = mgcos(angle)
v^2/r = 9.8m/s (cos (angle)
v^2 = 9.8 m/s (Rcos(angle))

Substitute that into v^2/2 = 9.8 m/s(R) - 9.8m/s(Rcos (angle)) and get:

9.8m/s Rcos (angle)) = 19.6 m/s(R) - 19.6m/s (Rcos (angle))

That reduces to:

cos (angle) = 2/3
so the angle must be 48.2 degrees


My teacher said it was wrong, can anyone assist me?
 
Last edited by a moderator:
Physics news on Phys.org
I a person is sking down a sphere, there is no "centripetal force"- there is no force on the person toward the center of the sphere. The only force is that of gravity, straight down.
 
A centripetal force is included in the problem. I didn't type the whole problem out.
 
The centripetal force is the force towards the center due to gravity and the normal... if the skier is moving along the sphere:

the net force towards the center = mv^2/r

component of gravity towards the center - normal force = mv^2/r

When the component of gravity towards the center becomes less than mv^2/r it is impossible for the skier to move along the sphere... force towards the center at this point cannot be mv^2/r because the normal force can't be negative...
 
I got it now! Turns out my teacher made an error. :smile:

Thanks everyone
 
Enderless said:
I got it now! Turns out my teacher made an error. :smile:

Thanks everyone

Cool. Looking at your solution now, I see it is exactly right.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
3K
Replies
12
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
4K
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
7
Views
3K
Replies
6
Views
2K