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## Homework Statement

You come to a river and you see a vine you will use to swing across. Your mass is 75.0 kg, the vine is 18.0 m long, and the vine breaks when under 655 N of tension.

a) at what angle from the vertical will the vine break?

b) what should be the maximum tension supported by the vine for you to safely cross the river?

## Homework Equations

T=mgcosθ+ m (v^2/r)

θ=cos^-1((T-m(v^2/r))/mg)

Tmax=mgcos(0)+m(v^2bottom/r)

Tmax=mg+m(v^2bottom/r)

## The Attempt at a Solution

How i would solve this problem is by using the formulas like, θ=cos^-1(T/mg)

θ=cos^-1(655/((75.0kg)(9.8m/s^2))

and get θ=27.0 degrees

and Tmax=mg

Tmax=(75.0kg)(9.8m/s^2)

=735 N

is this the correct approach?

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