Finding the Angle with Arctan: A Manual Approach

  • Thread starter Thread starter carlodelmundo
  • Start date Start date
  • Tags Tags
    Theta
Click For Summary

Homework Help Overview

The discussion revolves around finding the angle associated with the arctangent function, specifically in the context of a coordinate point in Quadrant 2. The original poster seeks to determine the angle without a calculator, focusing on manual methods for calculating arctan(-2).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the angle using the arctangent function and questions how to do so manually. Some participants suggest that a calculator is necessary for accurate results, while others explore alternative methods such as approximations and geometric interpretations.

Discussion Status

The discussion includes various perspectives on the feasibility of calculating arctan(-2) without a scientific calculator. Some participants provide insights into drawing triangles and using reference angles, while others emphasize the limitations of a four-function calculator for this type of problem.

Contextual Notes

Participants note the constraints of using only a four-function calculator and the implications this has for solving trigonometric problems in class. There is also mention of the original problem being from a practice question, which may influence the approach taken by participants.

carlodelmundo
Messages
133
Reaction score
0

Homework Statement



http://carlodm.com/images/mth.png


** Note: The above is from a PRACTICE question for my course.

Homework Equations



arctan x = (theta)


The Attempt at a Solution



So. (-3,6) is in Quadrant 2. To solve for this angle we use:

(pi) + arctan (-6/2) = (pi) + arctan (-2) = 2.034.

My question is:

How can I solve for arctan(-2) if I don't have a calculator? aka... how do I do it by hand?

Thanks
 
Last edited by a moderator:
Physics news on Phys.org
well you can't really do it by hand, you can approximate it, but you'd need a calculator for that.
 
I only have a four function calculator to solve these types of problems in class. Is it possible with a 4 function? Any other method?
 
If you're taking a class involving trig, you really should have a scientific calculator. A four-function calculator is not much use at this level.
 
Finding the arctangent is way overkill.

Just looking at the quadrant narrows things down to two possibilities. The right answer can be determined by splitting the quadrant into two parts.
 
Try drawing the triangle on a cartesian coordinate system. You can relate it to a similar triangle with bottom leg 1, left leg of 2, and by pythagorean theorem, hypotenuse of sqrt(5).

In this arrangement, there is reference angle for which sine of this reference angle is same as sine of pi minus reference angle.

My first result for this seems arcsin(ref.angle) = (2/5)*sqrt(5)

I would either use scientific calculator or table of trigonom functions to find the reference angle; then find actual requested angle by pi minus reference angle.
 
Here is diagram that I draw recently
http://img196.imageshack.us/img196/8480/arctan.png

Here is what I do. First draw the line between (-3,6) and (0,0). You can see what the angle is, but still can not determine it. The next step is to divide the quadrant on half, (180+90)/2 = 135. You can still see that it is still not too close. Again find the half between 135 and 90 (because the angle is between these ones), (135+90)/2 = 112.5. Now it is close to the right angle. So you can just continue doing the same process over and over again until you are satisfied with the result.

I hope I was helpful. :smile:
 
Last edited by a moderator:

Similar threads

  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K