Finding the angular frequency of an object

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t.kirschner99
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Homework Statement


An object undergoes simple harmonic motion along an x-axis with a period of 0.50s and amplitude of 29mm. Its position is x = 12mm when t = 0s. Determine the value of ω in the equation of motion. Suppose that ω > 0.

Homework Equations



$$ω = \frac {2π} {T}$$

The Attempt at a Solution



Earlier in the problem, I found that x(t) = Asin(ωt + ∅i) (which is confirmed correct). The question is asking for the angular frequency of an object going simple harmonic motion (no damping), so I am assuming I would need to just plug the period into the formula above. Thus:

$$ω = \frac {2π} {0.5s}.$$
$$= 12.57 \frac {rad} {s}$$

When I submit this answer though, it says it is incorrect. I've tried entering the solution as 4π rad/s (which it said the answer needed to be in decimal format) and 13 rad/s (which it said that the answer does not have the correct dimensions).
 
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t.kirschner99 said:
When I submit this answer though, it says it is incorrect. I've tried entering the solution as 4π rad/s (which it said the answer needed to be in decimal format) and 13 rad/s (which it said that the answer does not have the correct dimensions).
You don't say specifically, but it sounds like when you submitted 12.57rad/s it did not complain about the dimensions. If so, that suggests it is happy with the 13 as the numeric value.
Although the radian is a unit, most authorities maintain angles do not have dimension. You could try 13s-1.
 
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haruspex said:
You don't say specifically, but it sounds like when you submitted 12.57rad/s it did not complain about the dimensions. If so, that suggests it is happy with the 13 as the numeric value.
Although the radian is a unit, most authorities maintain angles do not have dimension. You could try 13s-1.

Thank you! 13s-1 was the correct answer.