Finding the angular resolution of a telescope

[Kieran12]

Homework Statement

An optical telescope has a diameter of 1.5m. It is placed at a site with 'seeing' of 1.0''. What is the expected resolution in arcseconds from observations made with the telescope at 1000nm? Give your answer to one decimal place

Homework Equations

Theta (rads) = 1.22 * (wavelength/diametre of aperture)

Rads * 180/pi = degrees

1 degree = 1*60*60 arcseconds

The Attempt at a Solution

So far, I have used the equation:

Theta = 1.22 * (wavelength / D) (where D = diametre of aperture).

Thus using this equation I have worked out that: 1.22 * (1000 * 10-9 / 1.5) = 813.33 * 10-9 rads = 0.167 arcseconds.

Where does seeing come into all this?? Its driving me mad!

 

[mfb]

Do you know how seeing is defined?

Both seeing and the telescope resolution will influence the angular resolution, unless one is negligible it is probably reasonable to combine their effects.