Finding the Area of Triangles with Adjoining Sides and Angles

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Homework Help Overview

The discussion revolves around finding the area of triangles using different formulas, particularly focusing on triangles with two adjacent sides and the included angle. The original poster is attempting to understand the application of the area formula A=1/2 ab sin C, as well as other area-related problems involving given sides and heights.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the area formula for triangles but questions the use of sin(45) in their calculations. They also present additional problems involving different side lengths and angles, seeking clarification on how to approach these problems.

Discussion Status

Some participants provide guidance on the original poster's calculations and suggest verifying trigonometric values. There is an ongoing exploration of how to find the base in a different triangle problem, with some participants suggesting the use of the Pythagorean theorem.

Contextual Notes

The original poster expresses difficulty with multiple area problems and seeks assistance, indicating a potential lack of understanding of the underlying concepts. There is mention of needing to find the base in one of the problems, which introduces additional complexity.

H.M. Murdock
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Im trying to teach myself some geometry on my own, but I am stuck since some weeks, with a couple of area problems of triangles. I ll really appreciate any help or advice about it.

The formulas for a triangle are:

A=1/2 bh and A=1/2 ab Sen C

The problem says:
-Find the area of a triangle that has two adyacent sides that are 5 and 4 ,and they include an angle that is 45º

I thought that the formula might be A=1/2 ab Sen C

so it would be A= 1/2 (4)(5)(sen 45) = 7.07106...

but the result on the book was = 5 square root of 2

Could I use "sen of 45" in that way? if not what is the correct procedure in order to do that problem?

There are some other similar problems that I can't understand as well:

-Find the area of a triangle that has two adjacent sides that are 8 and 12, and they include an angle that is 60º.

-Find the area of a triangle if two sides are 13 and 15, and the height over the third side is 12.

Im stuck with those ones since some weeks, I 'll really appreaciate any help.

Thanks a lot in advance.
 
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H.M. Murdock said:
I thought that the formula might be A=1/2 ab Sen C

so it would be A= 1/2 (4)(5)(sen 45) = 7.07106...

but the result on the book was = 5 square root of 2

Your answer is correct, but just expressed differently. Note that sin(45) = sqrt(2)/2--verify with a table of trigonometric values. A calculator does not explicitly reveal the factor, square root of 2.
 
buffordboy23 said:
Your answer is correct, but just expressed differently. Note that sin(45) = sqrt(2)/2--verify with a table of trigonometric values. A calculator does not explicitly reveal the factor, square root of 2.

Thanks a lot, I appreaciate it.

Im trying to solve this one now:

Find the area of a triangle if two sides are 13 and 15, and the height over the third side is 12.

Do I need to find the base in the problem? Should I use the pytagorean theorem to get the base in this problem? and if so what should be the procedure?

Thanks in advance for your time and help.
 
Yes. Find the base. Use the Pythagorean theorem. You have two right triangles with hypotenuses 13 and 15 and side 12. The sum of the other two sides is the base.
 
Use trigonometry my friend.
 
Dick said:
Yes. Find the base. Use the Pythagorean theorem. You have two right triangles with hypotenuses 13 and 15 and side 12. The sum of the other two sides is the base.

thanks a lot
 

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