Finding the Average: Solving Basic Pre-Algebra Problems

  • Thread starter Thread starter vincentm
  • Start date Start date
  • Tags Tags
    Algebra
Click For Summary

Homework Help Overview

The discussion revolves around finding the average (arithmetic mean) of a set of numbers: 8, 7, 7, 5, 3, 2, and 2. The original poster expresses a desire for guidance without receiving direct answers, indicating they are returning to school and seeking support in basic math concepts.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the method of calculating the average by summing the numbers and dividing by the count. There is a focus on understanding the arithmetic process involved in finding the mean.

Discussion Status

Some participants confirm the calculations presented, indicating a level of agreement on the arithmetic process used to arrive at the average. However, the original poster's request for guidance suggests that the discussion is still open for further exploration of the concepts involved.

Contextual Notes

The original poster emphasizes their need for assistance without wanting direct answers, highlighting their current learning context and the importance of understanding the underlying principles of the problem.

vincentm
Messages
322
Reaction score
3
I know this is basic stuff, but I'm barely geting back into school and starting off with a basic math class, so any help would be highly appreciated, i don't want the answers just to be pointed in the right direction. :smile:


'what is the average (arithmetic mean) of 8,7,7,5,3,2 and 2'

(a) [tex]3\frac{4}{7}[/tex]

(b) [tex]4\frac{5}{6}[/tex]

(c) [tex]4\frac{6}{7}[/tex]

(d) 5

(e) [tex]6\frac{4}{5}[/tex]
 
Physics news on Phys.org
Just add them all up, and divide by the total number of numbers you have.
 
so the answer is (c) [tex]4\frac{6}{7}[/tex]which i got by adding the numbers up which is 34 and dividied by that total which is 7, so 34 divided by 7 is 4 remainder 6 which gives me [tex]4\frac{6}{7}[/tex]right?
 
Last edited:
Looks right to me.
 
JasonRox said:
Looks right to me.


Thanks for your help.
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
39
Views
6K
  • · Replies 7 ·
Replies
7
Views
4K