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the roots are x= 3 and x = 6

what's the base of the numbers?

ok what I've done is I found the roots in decimal system which are

x1 = (11+sqrt(33))/2 and x2 = (11-sqrt(33)/2

then I said x1 = 3 and x2 = 6 so we have

3 = (11+sqrt(33)/2 <=> 6 = 11+sqrt(33) <=> -5 = sqrt(33) <=> 25 = 33 <=> 2b + 5 = 3b + 3 <=> b = 2

im doing the same for the second root

6 = (11-sqrt(33)/2 <=> 12 = 11 -sqrt(33) <=> 1 = -sqrt(33) <=> 1 = 33 <=> 1 = 3b + 3<=>

3b = -2 <=> b = -2/3

i know that my method is wrong, the correct answer is 8 but that's what I thought would solve this problem, it's the first time that I see this kind of problem, so if anyone could guide me I would apreciate it

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# Finding the base of numbers from a given equation

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