Finding the change in velocity from an acceleration vs time graph

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The discussion centers on calculating the change in velocity from an acceleration vs. time graph over the interval of 0 to 4 seconds. The initial calculation yielded -8 m/s, but the correct change in velocity is 8 m/s, indicating a positive increase. Participants clarify that while acceleration can decrease, it does not mean that velocity must also decrease; as long as acceleration remains positive, velocity continues to increase, albeit at a diminishing rate. The key takeaway is that a decreasing acceleration can still lead to an increasing velocity. Understanding this relationship is crucial for interpreting motion graphs accurately.
MattDutra123
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Homework Statement


The graph shows the variation with time t of the acceleration a of an object (graph attached).
What is the change in velocity of the object in the time interval 0 to 4s?

Homework Equations


a = v/t

The Attempt at a Solution


My initial answer was -8 m/s, by simply finding the area under the curve. However, the correct answer is 8 m/s (positive). I don't understand how acceleration could be decreasing if the velocity isn't. How can acceleration decrease when the velocity is increasing?
 

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MattDutra123 said:

Homework Statement


The graph shows the variation with time t of the acceleration a of an object (graph attached).
What is the change in velocity of the object in the time interval 0 to 4s?

Homework Equations


a = v/t

The Attempt at a Solution


My initial answer was -8 m/s, by simply finding the area under the curve. However, the correct answer is 8 m/s (positive). I don't understand how acceleration could be decreasing if the velocity isn't. How can acceleration decrease when the velocity is increasing?

Acceleration = rate of change of velocity, so as long as acceleration is positive, the velocity is increasing. In this case, the rate at which velocity increases becomes less as time passes, but it is still positive.
 
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